I just posted a simple implementation of WTTE-RNNs in Keras on GitHub: Keras Weibull Time-to-event Recurrent Neural Networks. I'll let you read up on the details in the linked information, but suffice it to say that this is a specific type of neural net that handles time-to-event prediction in a super intuitive way. If you're thinking of building a model to predict (rather than understand) churn, I'd definitely consider giving this a shot. And with Keras, implementing the model is pretty darn easy.

As proof of the model's effectiveness, here's my demo model (with absolutely no optimization) predicting the remaining useful life of jet engines. It's not perfect by any means, but it's definitely giving a pass to engines that are in the clear, and flagging ones that are more likely to fail (plus a few false positives). I have no idea how much better it could do with some tweaking:

*Also, if anybody's curious as to why I've been in a bit of a post desert lately, my wife and I recently had a baby and I haven't been giving as much thought to the blog. However, I have some ideas brewing!*

JimmyMarch 24, 2017 / 4:32 amDear blogger,

What is the relation between test_x and test_y? I thought the data in the test_y were life, but obviously they were not.

daynebattenMarch 24, 2017 / 9:52 amIn the demo code I posted, test_y is a (samples, 2) tensor containing time-to-event (y) and a 0/1 event indicator (u), specifically for the testing data (as opposed to the training data). The event indicator for test_y is always 1, because this is the true remaining lifetime for all these engines.

test_x is simply a history of sensor readings for each engine, used to make predictions about its remaining useful life.

If the model is working well, when it’s fed test_x and asked to make predictions, it should generate predictions roughly equivalent to the lifetimes in test_y.

Hope that helps.

JimmyMarch 28, 2017 / 3:09 amThanks for your reply. It has been very helpful. I want to try to predict the real-time remaining life of the engines. Do you have any suggestion?

daynebattenMarch 28, 2017 / 7:40 amThat’s actually exactly what the demo code is for… the alpha and beta parameters in the output describe a Weibull distribution showing the propensity for each engine to fail over future time.

If you need a point estimate of life remaining (like I’ve used for the graph above), you can simply set the Weibull survivor function equal to .5 using the output alpha and beta and solve for time. The survivor function is exp(-(t/a)^b). Set it equal to .5 and solve for t and you get a(-ln(.5))^(1/b).

Hope that helps.

JimmyMarch 30, 2017 / 2:53 amI calculated the remaining useful life and I found the values are quite far from the actual one. Take engine 1 as an example, the predicted result was [ 112. 1. 218.93415833 4.13228035]. The t I solved is about

219*(-ln(.5))^(1/4)=196,

but the actual value is 31. Why is it so different?

Thanks!

daynebattenMarch 30, 2017 / 6:14 amIf you look at the code, you’ll see that the output prints the test_y values next to the predictions, so that 112 in your output is the actual remaining life of that engine. Not sure where you got 31 from.

A few other things to remember:

1) This prediction is saying the engine has a 50% chance of surviving to day 196. We’d expect some engines to fail before then and some to fail after then.

2) This is machine learning, not black magic. No predictions are going to be perfect.

3) This is a demo and I made no attempts to optimize this model whatsoever. It’s entirely possible that making some tweaks to the model (additional layers of neurons, for example) could dramatically improve performance. Feel free to mess around.

JimmyMarch 30, 2017 / 10:31 amSorry about my stupid questions. XD

I have been learning LSTM recently and I have not completed a single model of RNN (LSTM). Your example is wonderful and I am sure I will learn a lot from it. The value 31 was learned from the data test_x. According to the data, engine 1 ran 31 cycles and failed, so I think TTE value should be 31.(Am I right?) However, the value is 112 in test_y.

Thanks!

daynebattenMarch 30, 2017 / 1:19 pmNo problem at all. The best way to learn is by taking on new challenges and muddling through.

Best of luck!

(Don’t have time to go hunt down the 31 right now, but if the 31 came from test_x, it’s some kind of sensor reading from the engine.)

PhillipApril 1, 2017 / 4:28 amMr. Batten,

I am a doctoral student at NC state interested in discussing a section of your recent dissertation with you. If willing, please email me at your earliest convenience.

daynebattenApril 3, 2017 / 7:43 amIf you’re looking to talk about this model, I’d be happy to have a conversation with you, but I haven’t written a dissertation on the subject (or any subject, for that matter)… Perhaps you’re referring to Egil Martinsson’s thesis?

I’ll send you an email offline, though I’m also mildly concerned this is trolling what with it being April 1 and all?

Natalia ConnollyApril 12, 2017 / 1:17 pmHi Dayne,

Thank you for making your code available on github! This is really cool stuff.

A quick question: where did you get the true time-to-event numbers (the ones in test_y)? Was it part of the NASA dataset?

daynebattenApril 12, 2017 / 1:46 pmHi Natalia,

Yes, it was part of the NASA data set. The files starting with RUL indicate the remaining useful life for each engine in the test data files, which start with test_.

The organization of the data is admittedly not the best…

Thanks!

AshwinMay 20, 2017 / 9:43 amMr. Batten,

Thanks for the simple write up and code! I am still learning the workings and have a basic question –

The RUL = a(-ln(.5))^(1/b) that you mentioned to Jimmy’s post, is it absolute time or a percentage of the max time of the engine?

Cheers!

Ashwin

daynebattenMay 22, 2017 / 3:22 pmThanks for writing. That should be absolute time!

Alberto AlbiolMay 22, 2017 / 5:22 amExcellent work, I have been digging into your code to get some light on recurrent models.

I have two questions:

1- Do you think that the result would be very different without masking?, you have already left-padded the sequences with zeros

2- You are using a sliding window of 100 timesteps, but another option is using a stateful char-rnn, so the network can remember the whole history and reset the state for each engine?, have you tried something like this?. I think that the advantage of your approach is that you can shuffle the training samples….

daynebattenMay 22, 2017 / 3:26 pmGood questions.

1) I’m not an expert on NNs, so I’m not 100% sure, but I expect it wouldn’t make a super-big difference. I’d imagine the network would learn that having everything set to 0s is basically useless information and begin to ignore it. Not ideal to have some of your model’s knowledge dedicated to that, though, if it’s not necessary.

2) Yes, you could use a stateful char-rnn, but there’d be two downsides. First, you could only back-propagate through time for as many time steps as you had in each batch. If you kept, say, 10 time-steps per batch, this might not matter… but I don’t know. I haven’t played with this dummy model much. Second, there’s just some Keras challenges involved in managing batches when you have time series of differing lengths. It’s not anything that can’t be accomplished, but it would be some extra coding.

Thanks for writing!

JackMay 24, 2017 / 1:46 amThanks for posting this. On which hardware did you train the model and how much time did it take?

daynebattenMay 24, 2017 / 8:09 amI trained the dummy model on my laptop (core i5). I don’t remember exactly how long it took, but definitely no more than an hour or so.

I’ve scaled this up to a different data set with 52 observations of 67 features for ~100k individuals. As with the jet engine data, this expanded to a full historical look-back for each period in which the individual was observed. It was a pretty big model. Trains on a p2.8xlarge in ec2 (8 Tesla k80s) in a couple hours…

DMJune 26, 2017 / 12:44 pmHi Dayne, thanks so much for taking the time to put this together. I’m trying to walk through the work you’ve done with the goal of spinning up my own churn prediction model. Downloading the data from the NASA site and running the code from your github page, I’ve plotted the predicted vs actual time to survival, similar to the graph you have near the bottom of your post.

I see similar patterns and clusters between our two plots, except the vertical bar in my plot is centered at around 90 days whereas yours it at 60. Without asking you to debug my code, and being aware of the randomness inherent in the model, is it possible that your plot was generated from a different model than what you posted?

Like I said, I pasted your code in its entirety so I want to verify the input to the chart before I begin diving into other possible discrepancies. Again, thanks a ton for the all the work you’ve done, it’s a great simplified version of Egil’s work and has been really helpful for me to wrap my head around this.

DMJune 26, 2017 / 5:10 pmNevermind! It was an issue in my code, somehow ðŸ™‚

slawJune 29, 2017 / 2:44 pmGreat post. I had a question about the normalization. If I train a model on a single feature that has raw values between 0-0.5 and the test data has values between 0-1.0 then wouldn’t the separate normalizations of the training and test sets be inconsistent? It would be even worse if the new incoming unlabeled data had values between 0-2.0 and so the normalization would be inconsistent across all three data sets. Is there a good way to address this?

daynebattenJuly 6, 2017 / 7:33 amThis is just a bug… thanks for pointing it out. I actually noticed it in a private project a couple weeks ago and haven’t gotten around to fixing it in the public repo. I’ll knock that out now.

pupAugust 16, 2017 / 7:35 amHi Dayne – How do you think this will extrapolate to a retail customer churn model which is not subscription based. Instead customers simply stop coming. Would the analogue to RUL be the number of days to the last transaction?

Thanks!

daynebattenAugust 28, 2017 / 8:52 pmThanks for writing! I think it would map on quite well. In fact, in Egil Martinsson’s original work (cited above), he was envisioning just such a scenario!

AlexanderSeptember 4, 2017 / 12:36 pmDo you know how to deal with irregular observations? For example during let’s say 12 months period there could be various number of observations for each subject at various dates during this 12 month period (pretty much random dates and number of events per subject). Number, frequency, and parameters taken during each observation could be related to the probability of the event – for example if device is brought in for repair multiple times during last 12 months it is obviously will affect its chance of a catastrophic failure in the next 30 days.

daynebattenSeptember 6, 2017 / 11:16 amHmmm… that’s an interesting question and, unfortunately, I don’t know that I have a great answer. It may be worth looking into the application of RNNs in situations with varying amounts of time between observations? I’d imagine somebody else has faced this issue before, though maybe in a different context.

EdSeptember 22, 2017 / 5:14 pmFirst of all GREAT THANKS!

I work with surv analysis in R (rfsrs etc)

i’ve read your post

https://github.com/daynebatten/keras-wtte-rnn

please, tell where i can read description of the dataset?

jet engine failure

I cann’t find this

https://ti.arc.nasa.gov/tech/dash/pcoe/prognostic-data-repository/

I guess column 0 means # of engine

column 1 means # of timestep

Do I understand correctly?

Where in train data we can see sensored or unsensored event?

thanks a lot

daynebattenSeptember 25, 2017 / 8:16 amThanks for the kind words… The jet engine failure data is #6 on the linked page… “Turbofan Engine Degradation Simulation Data Set.” There’s an included readme and other resources.

I believe (though I didn’t go explicitly check, so you may want to verify) that all of the engines in the data set were followed until the end of their useful life, so there are no censored observations.

Ayub QuadriNovember 17, 2017 / 12:11 amHello Daynebatten,

Its a wonderful work with a beautiful dataset to understand the Time to a failure event, I want to know more about some of the parameters in the test_results which it generates, as per my understanding.

Test_results -> [ TTE, Event Indicator, Alpha, Beta]

where TTE -> actual value

Event Indicator -> yes or no [1/0]

Alpha -> some value

Beta -> some value

to calculate the predicted Time to failure do we need to feed it to the formula inverse CDF

1. The inverse cumulative distribution function is I(p) = alpha (-ln(P))^(1/beta)

or

2. Probability density function (PDF)

3. Cumulative density function (CDF)?

the formula for Weibull distribution function f(x), PDF, CDF, ICDF(p) is provided in http://www.real-statistics.com/other-key-distributions/weibull-distribution/

Please correct me if my assumption is wrong.

daynebattenNovember 17, 2017 / 9:14 amThere isn’t necessarily a “predicted time to failure” as a point value. Instead, alpha and beta give us information about the probability of failure over time. If you want to get a point estimate (as I did to make the graph in the GitHub ReadMe), you could look for the point in time where the survival function for the Weibull distribution crosses 50%. This is the point where the chance of having failed by that point goes over 50%, so it’s a defensible estimate for remaining useful life.

Ayub QuadriNovember 20, 2017 / 10:00 amI want to know more how did you calculate the ‘Predicted Remaining Useful life’

The outcome of mode is 4 fields

1. Actual RUL

2. Event Indicator

3. Alpha

4. Beta

it might be a silly question but please explain me how did you evaluate the Predicted RUL from the above outcomes.

Ayub QuadriNovember 21, 2017 / 2:17 pmplease help me out to understand the outcome generated by the model.

it gave me alpha, beta values but what would be the TTE?

can I feed that to Weibull function to predict the Remaining Useful Life (RLU)?

daynebattenNovember 22, 2017 / 8:45 pmPlease see my previous reply. There is no point value for predicted time to failure… instead there’s a distribution across future time.

For the purposes of that graph on GitHub, I did something quick and dirty – I looked for the point where the Weibull survival function crossed 50%. This is not exactly correct, but, as I said in the last post, it’s reasonable, and it gave me what I wanted – a quick and dirty way to plot my results against actual values and prove that the model learned something. If you’re looking for me to lay the math out for you, the survivor function is exp(-(t/a)^b). Set it equal to .5 and solve for t and you get a(-ln(.5))^(1/b). Plug in a and b and you get your estimate.

As it turns out (see pages 3-4 of the document linked below), the correct way to estimate expected future life is to integrate the survival function from 0 to infinity. Please, please, though… understand that neither of these are a prediction that the subject will experience a failure on that particular day, it’s just our best estimate for how long it will survive.

http://data.princeton.edu/wws509/notes/c7.pdf